Derivation of formula for general formula of sine equations

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SUMMARY

The discussion focuses on the derivation of the general formula for sine equations, specifically when sin(x) = a. The established formulas are x = 2nπ + sin^-1(a) and x = (2n + 1)π - sin^-1(a), along with the more general form x = nπ + (-1)^n sin^-1(a). Participants clarify how to derive the general formula by analyzing the behavior of n as even or odd, leading to a deeper understanding of the sine function's periodicity.

PREREQUISITES
  • Understanding of trigonometric functions, specifically sine.
  • Familiarity with inverse trigonometric functions, particularly sin^-1.
  • Knowledge of periodic functions and their properties.
  • Basic algebraic manipulation skills.
NEXT STEPS
  • Study the periodic properties of sine functions in depth.
  • Learn about the derivation of inverse trigonometric functions.
  • Explore the implications of even and odd functions in trigonometry.
  • Investigate applications of sine equations in real-world scenarios.
USEFUL FOR

Students of mathematics, educators teaching trigonometry, and anyone looking to deepen their understanding of sine equations and their general solutions.

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My book gives the following formulas for the general solution of sine equations (if sin(x)=a)

[tex]x=2n\pi + sin^-^1(a)[/tex]

and

[tex]x=(2n+1)\pi - sin^-^1(a)[/tex]

Alternatively
[tex]x=n\pi + (-1)^nsin^-^1(a)[/tex]

But it doesn't explain how it got them. I can easily see how they got the first two but I have no idea how they got the more general one. My teacher didn't show how it was derived either...just threw a bunch of formulas at us to remember
 
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Take the equation

[tex]x=n\pi + (-1)^n \sin^{-1}(a)[/tex]

What happens if you take n even (that is: of the form 2k) and what happens if you take n odd (that is: of the form 2k+1)??
 
^ Wow, it seems so obvious now but I never would've seen had you not pointed me in the right direction, thank you!
 

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