Derivation of graph of v against u

  • Thread starter Thread starter desmond iking
  • Start date Start date
  • Tags Tags
    Derivation Graph
Click For Summary

Homework Help Overview

The discussion revolves around deriving the graph of velocity (v) against initial velocity (u) in a physics context. The original poster expresses difficulty in determining the shape of the graph and identifying a specific point (2f, 2f).

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants explore the intersection of the curves u=v and 1/u + 1/v = 1/f, questioning how to manipulate these equations to derive the relationship between v and u.

Discussion Status

Some participants have provided insights on how to approach the problem, suggesting methods for inserting one equation into another. The original poster has indicated progress after consulting additional resources, though the overall discussion remains open-ended.

Contextual Notes

The original poster mentions challenges with notation and clarity in the problem statement, which may affect the discussion's direction. There is also a reference to a specific form of the equation that could be useful for deriving the graph.

desmond iking
Messages
284
Reaction score
2

Homework Statement


This is the graph of v against u .
i am having problem of getting the shape of graph and getting the point (2f, 2f) . can anyone teach me how to derive it?


Homework Equations





The Attempt at a Solution


sorry. i don't know how to use LATEX. it may be quite untidy if i type it using / sign for all the equation.

so , i have did it beside the graph in the photo . hopefully you guys can understand .
 

Attachments

  • DSC_0073.jpg
    DSC_0073.jpg
    41.2 KB · Views: 1,130
Physics news on Phys.org
The question is a bit unclear. Is this the full problem exactly as stated?

It seems you want to find the point where the curves u=v and 1/u + 1/v = 1/f intersect. What happens if you insert the first relation into the second and solve for v?
 
  • Like
Likes   Reactions: 1 person
Orodruin said:
The question is a bit unclear. Is this the full problem exactly as stated?

It seems you want to find the point where the curves u=v and 1/u + 1/v = 1/f intersect. What happens if you insert the first relation into the second and solve for v?

this is not a question actually. it's just a note. Can you explain further? i am actually finding v against u in my working. to get the shape of the graph. unfortunealy, i got stucked.
 
desmond iking said:
this is not a question actually. it's just a note. Can you explain further? i am actually finding v against u in my working. to get the shape of the graph. unfortunealy, i got stucked.

See if you can get the equation into the form ##v - A = \frac B{u-C}##
 
  • Like
Likes   Reactions: 1 person
thanks , after referring to the old book, i managed to understand it.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
982
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 22 ·
Replies
22
Views
4K
Replies
16
Views
5K
  • · Replies 10 ·
Replies
10
Views
2K