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Derivation of graph of v against u

  1. Aug 23, 2014 #1
    1. The problem statement, all variables and given/known data
    This is the graph of v against u .
    i am having problem of getting the shape of graph and getting the point (2f, 2f) . can anyone teach me how to derive it?

    2. Relevant equations

    3. The attempt at a solution
    sorry. i dont know how to use LATEX. it may be quite untidy if i type it using / sign for all the equation.

    so , i have did it beside the graph in the photo . hopefully you guys can understand .

    Attached Files:

  2. jcsd
  3. Aug 23, 2014 #2


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    The question is a bit unclear. Is this the full problem exactly as stated?

    It seems you want to find the point where the curves u=v and 1/u + 1/v = 1/f intersect. What happens if you insert the first relation into the second and solve for v?
  4. Aug 23, 2014 #3
    this is not a question actually. it's just a note. Can you explain further? i am actually finding v against u in my working. to get the shape of the graph. unfortunealy, i got stucked.
  5. Aug 23, 2014 #4


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    See if you can get the equation into the form ##v - A = \frac B{u-C}##
  6. Aug 23, 2014 #5
    thanks , after referring to the old book, i managed to understand it.
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