- #1
MathematicalPhysicist
Gold Member
- 4,699
- 372
- TL;DR Summary
- Trying to derive Eq. (8.25) for Riemann tensor in the book of Schutz's in GR.
According to Schutz's second edition book, the equation for Riemann tensor to first order in ##h_{\mu\nu}## is:
$$R_{\alpha\beta\mu\nu}= \frac{1}{2}(h_{\alpha \nu,\beta \mu}+h_{\beta\mu,\alpha\nu}-h_{\alpha\mu,\beta \nu}-h_{\beta \nu , \alpha \mu})$$
which (as stated in the book) can be derived easily by using Eq. (8.12) which is:
$$g_{\alpha \beta}=\eta_{\alpha \beta}+h_{\alpha\beta}$$
All this is covered in pages 189-192.
How to derive the above identity? and how to derive the n-th order in ##h_{\mu\nu}## equation for Riemann tensor?
How come this equation is of first order in ##h_{\mu\nu}## if the terms in the above equation are second order derivatives of ##h##.
Thanks in advance!
$$R_{\alpha\beta\mu\nu}= \frac{1}{2}(h_{\alpha \nu,\beta \mu}+h_{\beta\mu,\alpha\nu}-h_{\alpha\mu,\beta \nu}-h_{\beta \nu , \alpha \mu})$$
which (as stated in the book) can be derived easily by using Eq. (8.12) which is:
$$g_{\alpha \beta}=\eta_{\alpha \beta}+h_{\alpha\beta}$$
All this is covered in pages 189-192.
How to derive the above identity? and how to derive the n-th order in ##h_{\mu\nu}## equation for Riemann tensor?
How come this equation is of first order in ##h_{\mu\nu}## if the terms in the above equation are second order derivatives of ##h##.
Thanks in advance!