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Forums
Physics
Special and General Relativity
Deriving Special Relativity Formulae Steps
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[QUOTE="Clever Penguin, post: 5493611, member: 593190"] I was bored, so I decided to derive the special relativity formulae. I drew the following diagram of a light clock: [ATTACH=full]101802[/ATTACH] In order to find t, I did sinθ=d/ct Which gives tsinθ=d/c Which gives t=d/csinθ If v = 0, vt = 0, and θ = 90 sin90 = 1 t = d/csinθ = d/c We call this t[SUB]0[/SUB]If v is greater than 0, vt is greater than zero, and θ is less than 90 sin90 is less than1 t = d/csinθ is greater than d/c We use Pythagoras to get t[SUB]0[/SUB]=t(1- (v[SUP]2[/SUP]/c[SUP]2[/SUP]))[SUP]-1/2[/SUP] What are the steps involved in getting to this answer? [/QUOTE]
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Physics
Special and General Relativity
Deriving Special Relativity Formulae Steps
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