- #1

Clever Penguin

- 74

- 20

I was bored, so I decided to derive the special relativity formulae.

I drew the following diagram of a light clock:

In order to find t, I did sinθ=d/ct

Which gives tsinθ=d/c

Which gives t=d/csinθ

If v = 0, vt = 0, and θ = 90

sin90 = 1

t = d/csinθ = d/c

We call this t

sin90 is less than1

t = d/csinθ is greater than d/c

We use Pythagoras to get t

What are the steps involved in getting to this answer?

I drew the following diagram of a light clock:

In order to find t, I did sinθ=d/ct

Which gives tsinθ=d/c

Which gives t=d/csinθ

If v = 0, vt = 0, and θ = 90

sin90 = 1

t = d/csinθ = d/c

We call this t

_{0}If v is greater than 0, vt is greater than zero, and θ is less than 90sin90 is less than1

t = d/csinθ is greater than d/c

We use Pythagoras to get t

_{0}=t(1- (v^{2}/c^{2}))^{-1/2}What are the steps involved in getting to this answer?