A Derivation of the Vacuum Einstein Equations: Understanding ln det g = 1

  • A
  • Thread starter Thread starter PGaccount
  • Start date Start date
PGaccount
Messages
85
Reaction score
25
I read somewhere that the vacuum Einstein equations can be written as

ln det g = 1

Does anyone know the derivation of this?
 
Last edited:
Physics news on Phys.org
PrashantGokaraju said:
I read somewhere...
Where?
 
Green Schwarz Witten, Volume II. page 440
 
PrashantGokaraju said:
I read somewhere that the vacuum Einstein equations can be written as

ln det g = 0

Does anyone know the derivation of this?
That is not the same as Ricci=0.
 
How can one equation contain all the information of 1/2*D*(D+1) equations?
 
That is what GSW says. Can someone look at it?
 
There is context that you haven't provided. They don't say that this is the vacuum Einsein equations. They say that the Ricci = 0 for a Kahler manifold is equivalent to ln(det g) = 1.
 
  • Like
Likes Martin Scholtz and weirdoguy
PrashantGokaraju said:
I read somewhere that the vacuum Einstein equations can be written as

ln det g = 1

Does anyone know the derivation of this?

This cannot be true since it is not a differential equation for the metric. #Ric=0# are vacuum Einstein's equations and thus 2nd derivatives must appear. I don't have the book you cite, can you give us some context?
 
martinbn said:
There is context that you haven't provided. They don't say that this is the vacuum Einsein equations. They say that the Ricci = 0 for a Kahler manifold is equivalent to ln(det g) = 1.

Thanks, I didn't know this.
 
Back
Top