Derivation of torsion equations

Click For Summary
SUMMARY

The discussion centers on the derivation of the torsion modulus equation, C=(32LQ)/(\pid^4), used in a lab involving a torsional pendulum. Key components include the torsion constant Q, the length L of the rod, and its diameter d. The user successfully derived the torsion constant formula Q=[(2\pi)^2]*[I/(T^2)], where I represents the moment of inertia and T is the period of the pendulum. The conversation highlights the need for a professional explanation and example for a lab report on torsional pendulums.

PREREQUISITES
  • Understanding of torsion and torsional pendulums
  • Familiarity with moment of inertia calculations
  • Knowledge of oscillation periods in physics
  • Basic grasp of mathematical derivations in physics
NEXT STEPS
  • Research the derivation of the torsion modulus equation in detail
  • Study the principles of torsional pendulums and their applications
  • Learn about calculating moment of inertia for various shapes
  • Explore lab report writing techniques specific to physics experiments
USEFUL FOR

Students in physics courses, particularly those working on lab experiments involving torsional pendulums, as well as educators seeking to provide clear explanations of torsion concepts.

ckeep
Messages
1
Reaction score
0

Homework Statement


This is for a lab involving a torsional pendulum. We are given the equation below to use, but having not covered torsion, the lab manual says that "The student should look up the derivation of this formula."


Homework Equations


The equation we're asked to find the derivation for is:

C=(32LQ)/(\pid^4)

where C is the torsion modulus of the rod, Q is the torsion constant of the rod, L is the length of the rod, and d is the diameter of the rod.


The Attempt at a Solution



I have already derived the formula Q=[(2\pi)^2]*[I/(T^2)]

where Q is the torsion constant of the pendulum's rod, I is the moment of inertia of the object on the pendulum, and T is its period, but I've been entirely unable to find anything further in my book or on the internet.
 
Physics news on Phys.org

Similar threads

  • · Replies 21 ·
Replies
21
Views
3K
Replies
5
Views
948
  • · Replies 1 ·
Replies
1
Views
7K
Replies
8
Views
2K
Replies
3
Views
2K
Replies
5
Views
3K
  • · Replies 14 ·
Replies
14
Views
4K
  • · Replies 2 ·
Replies
2
Views
9K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K