Derivative as a rate if change - is this correct?

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SUMMARY

The discussion centers on calculating the displacement of a moving body given its position function s = f(t) = t^2 + 24t - 1 over the interval 0 <= t <= 8 seconds. The user correctly derived the velocity function s' = 2t + 24 and solved for the time when the velocity equals 34 m/s, resulting in t = 5 seconds. The calculated displacement from t = 3 seconds to t = 5 seconds is confirmed to be 64 meters, validating the user's approach and calculations.

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donjt81
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I did this problem but wasnt sure if I did it right. Can anyone check it and see if my approach is correct?

here is the question:
The position of a moving body is given by s = f(t) = t^2 + 24t -1 for 0 <= t <= 8 where s is measured in meters and t in sec. Find the body's displacement for the time interval t = 3 to the time when the velocity is 34 m/s.

here is what i did:
s' = velocity = 2t + 24
34 = 2t + 24
t = 5

so the time interval is 3 <= t <= 5
t + delta t = 5
t = 3

displacement = f(t + delta t) - f(t)
= (5^2 + 24*5 - 1) - (3^2 + 24*3 - 1)
= 144 - 80
= 64 meters

I am wondering if this is correct. I wonder why they put the interval 0 <= t <= 8 ... maybe to throw us off. i don't know...

thanks in advance
 
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yeah that's correct.
 
thanks a lot!
 

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