Derivative of a Quadratic Function: Understanding the Use of cis(x)

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Homework Help Overview

The discussion revolves around finding the derivative of the quadratic function -x^2 - 2x + 8, with a particular focus on the use of the cis function in the context of derivatives and complex numbers.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the appropriateness of using the cis function in the context of derivatives, question the teacher's feedback, and discuss the implications of representing negative numbers using cis(pi).

Discussion Status

The discussion is ongoing, with participants sharing different perspectives on the use of the cis function and its acceptance in academic settings. Some suggest sticking to conventional methods for clarity, while others express curiosity about the mathematical properties involved.

Contextual Notes

There is a mention of the AP test context, indicating that certain conventions may be expected. Participants also note potential unfamiliarity with the cis function among educators.

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Homework Statement



Hi,

My teacher marked me wrong when I was asked to find the derivative of
-x^2 - 2x + 8
it was a review for the AP test were we just review everything
and I put
2cis(pi)x - 2
she marked it wrong and put a question mark over cis(pi)...

What's up with this teacher?
Do you think if I used the sis function on the AP test they would mark it wrong? It's not wrong at all...

Homework Equations





The Attempt at a Solution

 
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I mean technically
x - 2 = x + (-1)2 = x + cis(pi)2
 
It's high school, so your teacher is probably unfamiliar with \mathrm{cis}(\theta). For the AP test, I'd recommend you stick to \frac{d}{dx}( -x^2-2x+8) = -2x-2.

I like it, though. :smile:
 
So is there no such thing as a negative number at all sense every negative number is really just cis(pi) times a positive number? Is that why
x - 2
is really just
x + (-1)2
I always thought that was a strange property myself, simply just change the sign to positive and multiple 2 by (-1)...
 
No, the existence of the cis function does not imply that there are no negative numbers. cis(pi) evaluates to a negative number, so you are just writing a negative number as a product of a positive number and -1.
 
At least write ei π
writing cis is just silly
 

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