Derivative of an inverse function

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Homework Help Overview

The discussion revolves around finding the derivatives of inverse functions, specifically evaluating \((f^{-1})'(13)\) and \((f^{-1})'(6.5)\) for given functions \(f(x)\). Participants are exploring the relationship between a function and its inverse, as well as the implications of differentiating both sides of a function-inverse relationship.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Some participants suggest using the relationship \(f(f^{-1}(x))=x\) and differentiating both sides, while others question the correctness of the original poster's approach and the orientation of their work. There is also a discussion about the importance of typing out problems instead of posting images.

Discussion Status

The discussion is ongoing, with participants providing hints and guidance on the relationship between \(f'(x)\) and \((f^{-1})'(y)\). There is a mix of interpretations regarding the original poster's method, and some participants express frustration over the use of images instead of text.

Contextual Notes

Participants note that the original poster's images may not be oriented correctly, which could hinder understanding. There is also a mention of the need for clarity in problem statements to facilitate better assistance.

thegoosegirl42
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Homework Statement


I will post a picture of the problem and then the second picture will be my work. The problems are the first two.

Homework Equations

The Attempt at a Solution


I didn't know how to do this at first so I don't know if I am doing it correctly now. Also I don't know the correct answer.
 

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Try using ##f(f^{-1}(x))=x ## and differentiate both sides. EDIT I am assuming the necessary conditions hold.
 
Last edited:
Please don't post images in lieu of typing out the problem statement and work.

The problems are to find (a) ##(f^{-1})'(13)## given that ##f(x)=2x^3-7x-20##, and (b) ##(f^{-1})'(6.5)## given that ##f(x) = \frac{2}{x^2}+3x##. (Would it have killed you to type that out?)

Your approach isn't correct. For one thing, you're writing upside down. What's more important, you're finding ##(f')^{-1}##, but you're asked to find ##(f^{-1})'## evaluated at the given point.

Use WWGD's hint (or look in your textbook or notes) to find the relationship between ##f'(x)## and ##(f^{-1})'(y)## where ##y=f(x)##. You could also think about how the slope of the curve at a point changes when you reflect the curve about the line y=x.
 
vela said:
For one thing, you're writing upside down.
She might be writing the right way up, but the posted image of her work is upside-down.
@thegoosegirl42, if you post images, please take care to post them with the right orientation. Many helpers won't bother with posts where the work is shown in an image, let alone where the image is sideways or upside-down.
 
Mark44 said:
She might be writing the right way up, but the posted image of her work is upside-down.
@thegoosegirl42, if you post images, please take care to post them with the right orientation. Many helpers won't bother with posts where the work is shown in an image, let alone where the image is sideways or upside-down.
Ya, I didn't check to make sure if it was oriented correctly. I just assumed it was.
 
vela said:
Please don't post images in lieu of typing out the problem statement and work.

The problems are to find (a) ##(f^{-1})'(13)## given that ##f(x)=2x^3-7x-20##, and (b) ##(f^{-1})'(6.5)## given that ##f(x) = \frac{2}{x^2}+3x##. (Would it have killed you to type that out?)

Your approach isn't correct. For one thing, you're writing upside down. What's more important, you're finding ##(f')^{-1}##, but you're asked to find ##(f^{-1})'## evaluated at the given point.

Use WWGD's hint (or look in your textbook or notes) to find the relationship between ##f'(x)## and ##(f^{-1})'(y)## where ##y=f(x)##. You could also think about how the slope of the curve at a point changes when you reflect the curve about the line y=x.
I figured posting a picture would be easier for people to see than typing it out. I for one don't like these problems typed out.
 
thegoosegirl42 said:
I figured posting a picture would be easier for people to see than typing it out. I for one don't like these problems typed out.
It's actually easier for us if you type the problems. That way we can insert a comment at the exact place where something is wrong. With an image, we can't do that, and we have to describe where the error is.
 

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