Derivative of cos(e^-θ^2) using the chain rule | Power and exponential rules

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SUMMARY

The derivative of the function cos(e2) is calculated using the chain rule and results in -sin(e2) * e-2θ * e2. The process involves setting u = e2 and applying the chain rule twice, leading to the final expression -sin(u) * du, where du = -2θe2dθ. This method effectively demonstrates the application of both the chain rule and the power rule in differentiation.

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Homework Statement


Find the derivative of the following

cos(e^-θ^2)


Homework Equations


cos=-sin
e^x=e^x
power rule


The Attempt at a Solution


So I have gotten this far: -sin(e^-θ^2) * ... but then i don't know where to go. Would I treat the -θ^2 as the next step inwards? My best guess would be this:

-sin(e^-θ^2) * e^-2θ * e^-θ^2
 
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This is chain rule inside of the chain rule.

So, [tex]{\cos(e^{-θ^2})}[/tex] let [tex]u=e^{-θ^2}[/tex] to find du, let[tex]v=-θ^2[/tex][tex]dv=-2θd{\theta}[/tex] so [tex]du=-2θe^{-θ^2}d{\theta}[/tex] and finally [tex]{\frac{d({cos(u)})}{du}=-{sin(u)}du}[/tex]
 
Last edited:
Perfect
 

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