Derivative of Dirac Delta Distribution

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Discussion Overview

The discussion centers on the derivative of the Dirac delta distribution, ##\delta(t)##, exploring the nature of distributional derivatives and the requirements for test functions. Participants examine the implications of differentiating distributions and the conditions under which these operations are defined.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions how to take the derivative of the Dirac delta distribution, noting uncertainty about the applicability of distributional derivative theorems.
  • Another participant asserts that a distribution will always have a distributional derivative, referencing external material for support.
  • It is proposed that the derivative of the Dirac delta acts on a test function ##f(t)## by returning ##-f'(0)##, which requires the test function to be differentiable at zero.
  • A participant raises a concern about the nature of test functions, suggesting that if they are ##C^{\infty}## and zero is outside their support, then ##f'## would be zero.
  • Another participant argues that test functions can be defined in various ways, including discontinuous spaces, and emphasizes that the minimal requirement for the Dirac delta is existence at zero.

Areas of Agreement / Disagreement

Participants express differing views on the nature and requirements of test functions, particularly regarding their differentiability and support. The discussion remains unresolved regarding the implications of these definitions on the derivative of the Dirac delta distribution.

Contextual Notes

There are limitations regarding the assumptions about test functions and their differentiability, as well as the implications of defining test functions outside the traditional ##C^{\infty}## framework. These aspects are not fully resolved in the discussion.

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Hello,

I am wondering about the derivative of the Dirac delta distribution ##\delta(t)##. I know:

$$\frac{d}{dt} u(t) = \delta(t)$$

So what is ##\frac{d}{dt} \delta(t)##?

How do we take the derivative of a distribution? I've heard about distributional derivatives, but I don't think any of those theorems apply here.
 
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The Dirac delta is the functional which takes a test function ##f(t)## and returns ##f(0)##. In order for this operation to be defined you need a test function which is defined at ##x=0## (ideally you also want continuity there as well).

The derivative of the Dirac delta is the functional which takes a test function ##f(t)## and returns ##-f'(0)##. This requires the test function to be differentiable at zero.

How do we take the derivative of a distribution? I've heard about distributional derivatives, but I don't think any of those theorems apply here.
The derivative of a distribution is the distributional derivative.
 
pwsnafu said:
The Dirac delta is the functional which takes a test function ##f(t)## and returns ##f(0)##. In order for this operation to be defined you need a test function which is defined at ##x=0## (ideally you also want continuity there as well).

The derivative of the Dirac delta is the functional which takes a test function ##f(t)## and returns ##-f'(0)##. This requires the test function to be differentiable at zero.

Aren't test functions ## C^{\infty} ## ? If 0 is outside of the support, then isn't ##f'=0 ## ?
 
WWGD said:
Aren't test functions ## C^{\infty} ## ?

You can define test functions however you want. For example you can define discontinuous test function spaces. In the case of Dirac the minimal requirement is existence at zero. It effectively means that the Dirac distribution reduces to the Dirac measure in this case (note that you can't take distributional derivative anymore).
 

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