Derivative of Exponential Function with Variable Exponent

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The derivative of the function y = 10^(1 - x^2) is calculated as y' = (10^(1 - x^2))(ln 10)(-2x). There is confusion regarding the simplification of this derivative compared to Wolfram Alpha's output. Users agree that the original derivative expression is correct and emphasize the importance of algebraic manipulation to verify results. The discussion highlights the preference for keeping the derivative in its factored form rather than expanding it unnecessarily. Overall, the conversation reinforces the validity of the derived expression while questioning the simplification process.
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Homework Statement


Find the derivative of:
y = 10^(1 - x^2)

Homework Equations


I get:
y' = (10^(1 - x^2))(ln 10)(-2x)

doing everything Wolfram does here:
http://www.wolframalpha.com/input/?i=derivative+10^(1+-+x^2)

I don't understand why it simplifies to Wolfram's final answer from what I got.

The Attempt at a Solution


Everything Wolfram does above.
 
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Your answer is fine. Wolfram's answer is weird.
 
But it's a great opportunity to use algebra to see if you're correct!

-22-x251-x2xln10

-21+1-x251-x2xln10

-2121-x251-x2xln10

-2(21-x251-x2)xln10

-2xln10(101-x2)
 
vela said:
Your answer is fine. Wolfram's answer is weird.

Thank you. BTW I wouldn't multiply the (10^(1 - x^2)) by (-2x) to get something like -20x^(1 - x^2) right? I'd write (-2x)(10^(1 - x^2))(ln 10)?
 
Right.
 
As in the latter?
 
Yes.
 
Alright then. Thanks a bunch : D
 

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