Derivative of Fraction using power rule

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SUMMARY

The derivative of the function f(x) = 3 - (3/5)x is calculated using the power rule. The constant term 3 has a derivative of 0, while the term involving x is rewritten as (3/5)x^-1. Applying the power rule results in f'(x) = -3/5x^-2, which can be expressed with positive exponents as f'(x) = 3/(5x^2). This process demonstrates the application of differentiation techniques for polynomial functions.

PREREQUISITES
  • Understanding of basic calculus concepts, specifically derivatives.
  • Familiarity with the power rule of differentiation.
  • Knowledge of rewriting expressions with negative exponents.
  • Ability to manipulate algebraic expressions involving fractions.
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  • Study the application of the power rule in more complex functions.
  • Learn about the implications of constant derivatives in calculus.
  • Explore the concept of rewriting expressions for easier differentiation.
  • Investigate common mistakes in derivative calculations and how to avoid them.
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Students learning calculus, educators teaching differentiation techniques, and anyone seeking to improve their understanding of polynomial derivatives.

Phyzwizz
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The problem:
f(x)=3-3/5x

So I'm perfectly fine with finding the derivatives with stuff but I wasn't sure about this one. Would this be 0 because there is a three in the numerator and no x?
Or would it be 3-1/51-1=3-1=2?
 
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Sorry, is that f(x) = 3 - \frac35 x or f(x) = 3 - \frac3{5x}?
 
f(x)=3−3/5x
The derivative of 3 is going to be zero because its a constant.
Bring the x to the numunator.

Then you get 3x^-1/5. Apply the power rule
You get:

(-1)3x^-1-1/5 = -3x^-2/5

Now rewrite with positive exponants:

f'(x)= 3/5x^2
 
Thanks, that was pretty easy!
 
Hi Windowmaker. The point of these forums is to help guide people to the solution, not to do it for them.
 
I aplogize, I am new here. I won't make that mistake in the future!
 
Last edited:
No problem. I made that mistake when I was new too. Have fun and enjoy the forums.
 

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