- #1
suspenc3
- 402
- 0
Hi, can anyone check my work?
[tex]y=tan^-^1(x-(1+x^2)^\frac{1}{2})[/tex]
[tex]y^1=\frac{1}{1+u^2}\frac{dy}{du}[/tex]
let u = (x-(1+x^2))
[tex]y^1=\frac{1}{1+[x-(1+x^2)]} [1-x(1+x^2)][/tex]
thanks
[tex]y=tan^-^1(x-(1+x^2)^\frac{1}{2})[/tex]
[tex]y^1=\frac{1}{1+u^2}\frac{dy}{du}[/tex]
let u = (x-(1+x^2))
[tex]y^1=\frac{1}{1+[x-(1+x^2)]} [1-x(1+x^2)][/tex]
thanks
Last edited: