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Hi, can anyone check my work?

[tex]y=tan^-^1(x-(1+x^2)^\frac{1}{2})[/tex]

[tex]y^1=\frac{1}{1+u^2}\frac{dy}{du}[/tex]

let u = (x-(1+x^2))

[tex]y^1=\frac{1}{1+[x-(1+x^2)]} [1-x(1+x^2)][/tex]

thanks

[tex]y=tan^-^1(x-(1+x^2)^\frac{1}{2})[/tex]

[tex]y^1=\frac{1}{1+u^2}\frac{dy}{du}[/tex]

let u = (x-(1+x^2))

[tex]y^1=\frac{1}{1+[x-(1+x^2)]} [1-x(1+x^2)][/tex]

thanks

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