Derivative of ln3: Simple Problem Solution

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Homework Help Overview

The problem involves finding the derivative of the natural logarithm function, specifically ln(2x^2 + 3). Participants are discussing the properties of logarithms and the differentiation process related to this expression.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to differentiate the function and are questioning the derivative of ln(3). There is confusion regarding the application of logarithmic properties and whether the derivative of a constant like ln(3) is zero or another value.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of logarithmic differentiation. Some have provided examples of differentiating similar logarithmic expressions, while others are still uncertain about the derivative of ln(3) and its implications.

Contextual Notes

There appears to be some misunderstanding regarding the properties of logarithms, particularly in relation to constants and the differentiation process. Participants are also navigating the implications of their attempts and the rules of logarithmic functions.

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Homework Statement


ln (2x^2 + 3)


Homework Equations


ln 2x^2 + ln 3


The Attempt at a Solution


(4x/2x^2) + (3/3)
(2x/x^2) + 1

I know this is a simple problem but what is the derivative of ln3? Is it 1 (3/3) or 0?
 
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properties of logs

[tex]\ln(ab)=\ln(a)+\ln(b)[/tex]

what you have is

[tex]\ln(a+b)=\ln(a+b)[/tex]

example

[tex]\ln(x^{2}+3)[/tex]

differentiating

[tex]\frac{2x}{x^{2}+3}[/tex]
 
Last edited:
rocophysics said:
example

[tex]\ln(x^2)[/tex]

differentiating

[tex]\frac{2x}{x^2}[/tex]

properties of logs

[tex]\ln(ab)=\ln(a)+\ln(b)[/tex]
Can't you distribute the ln to get lna + lnb? I don't know what the derivative of ln3 is? Is it 3/3 or 0/3.
 
BuBbLeS01 said:
Can't you distribute the ln to get lna + lnb? I don't know what the derivative of ln3 is? Is it 3/3 or 0/3.
i just updated my post, i clicked submit on accident while trying to preview.
 
Oh okay I see now. So it would be...
(4x)/(2x^2 + 3)
(2x)/(x^2 + 3)
 

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