Derivative of x^2sin(4x) + xcos^(-2x)

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SUMMARY

The derivative of the function y = x²sin(4x) + xcos^(-2x) is calculated using the chain rule. The correct derivative is confirmed as 2xsin(4x) + 4x²sin³(x)cos(x) + cos^(-2x) + 2xcos^(-3x)xsin(x). The discussion highlights the importance of clarity in notation, specifically avoiding ambiguous expressions like sin². Proper formatting and organization of work are essential for readability and understanding.

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  • Understanding of calculus, specifically differentiation techniques
  • Familiarity with the chain rule in calculus
  • Knowledge of trigonometric functions and their derivatives
  • Ability to interpret mathematical notation clearly
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  • Practice differentiating trigonometric functions, focusing on sin(x) and cos(x)
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TommG
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Need to find the Derivative using the chain rule

y = x2sin4(x) + xcos-2(x)

I am not sure where to start.

answer in book is
2xsin4(x) + 4x2sin3(x)cos(x) + cos-2(x) +2xcos-3(x) xsin(x)
 
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I am not sure if I did it right but I think I got the answer.

x2sin4(x)
2xsin4 took derivative of just x2
4x2sin3x derivative of just power of sin
cosx derivative of just sin

2xsin4(x)+4x2sin3(x)cos(x)

xcos-2(x)

cos-2 derivative of x
-2xcos-3(x) derivative of power of cos
-xsin(x) derivative of just cos

cos-2+2xcos-3(x)sin(x)

final answer
2xsin4(x)+4x2sin3(x)cos(x)+cos-2(x)+2xcos-3(x)xsin(x)
 
Last edited:
Yes, but your work is very strange and hard to read, and I think it makes it more difficult than it should be.

Also, tidy up your penmanship a bit. sin² doesn't mean anything.

Just some suggestions.
 

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