Derivative of x: Taking Derivatives of \sqrt{(10t-3)^{2} + (2t)^{2}}

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SUMMARY

The derivative of the function x = √((10t-3)² + (2t)²) is calculated as dx/dt = (208t - 60) / (2√(104t² - 60t + 9)). The solution involves applying the chain rule and simplifying the expression. The final result can be further simplified by dividing both the numerator and denominator by 2, leading to dx/dt = (104t - 30) / √(104t² - 60t + 9). This confirms the correctness of the derivative calculation.

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Homework Statement



x = [tex]\sqrt{(10t-3)^{2} + (2t)^{2}}[/tex]

Find the derivative

Homework Equations





The Attempt at a Solution



x = [tex]\sqrt{(10t-3)^{2} + (2t)^{2}}[/tex]

x = [tex]\sqrt{(104t^{2} - 60t + 9}[/tex]

dx = [tex]\frac{1}{2\sqrt{104t^{2} - 60t + 9}}[/tex](208t-60)

dx = [tex]\frac{208t-60}{2\sqrt{104t^{2} - 60t + 9}}[/tex]

 
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That's correct. :smile:

You can divide both nominator and denominator with 2.
 
But what you computed isn't dx. In your equations you should have

dx/dt = your answer.
 

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