- #1
jhe2
- 1
- 0
The answer for derivative of y=5tanx+4cotx is y'=-5cscx^2. But how come on math help the answer is 5sec^2x-4csc^2x? I have a calculus test coming up and I really would appreciate if someone could explain!
- - - Updated - - -
Oh nvm I see my mistake!
- - - Updated - - -
Oh nvm I see my mistake!