Derive Dulong-Petit Law: Classical Kinetic Theory & Equipartition of Energy

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SUMMARY

The discussion focuses on deriving the classical Dulong-Petit law using kinetic theory and the equipartition of energy, specifically for the heat capacity at constant volume (Cv) of simple crystalline solids. The participant successfully establishes that Cv = 3R, where R is the ideal gas constant, by applying the equipartition theorem and calculating the energy associated with the degrees of freedom. The participant clarifies that the relationship Cv = Cp - R is not applicable for crystalline solids, emphasizing the need to derive heat capacity based on energy differences at varying temperatures.

PREREQUISITES
  • Kinetic theory of gases
  • Equipartition theorem
  • Heat capacity definitions (Cv and Cp)
  • Understanding of degrees of freedom in thermodynamics
NEXT STEPS
  • Study the derivation of the Dulong-Petit law in detail
  • Learn about the equipartition theorem applications in thermodynamics
  • Explore the differences between heat capacities for ideal gases and crystalline solids
  • Investigate the implications of temperature independence of heat capacity in classical physics
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This discussion is beneficial for physics students, thermodynamics enthusiasts, and anyone studying classical mechanics and heat capacity in solids.

Kiezel
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Homework Statement


hello everyone.
I have to derive the classical Dulong Petit law by using kinetic theory of gases and the equipartition of energy. The heat capacity at a constant V for simple crystalline solid. So, it should be explained without the quantum theory.

Homework Equations


Cv (heat capacity at constant v) = 3R = 3Nak (avogadro Na and k of boltmann's constant)
this is what I want to derive.

The Attempt at a Solution


the formula Cv = Cp - R is what I have derived from simple formula's like dU = dQ + dW.
If Cp = 4R then Cv = 3R, but why should this be the case?
I know it has something to do with the degrees of freedom. I think the solid at high temperature has 3 translational degrees of freedom and 3 vibrational degrees of freedom which would mean it has 6 degrees of freedom. How should I use this?

according to the equipartition theorem the energy of the degree of freedom is kT/2 thus with 6 degrees of freedom: E=Na6(kt/2)=3RT (because R=Nak)
so now I have an energy which is equal to 3RT

didn't the classical physics (around 1819) predict that the heat capacity was independent from the temperature (by only allowing the body to absorb very small amounts of heat)?

clearly I'm missing some vital next steps. can anybody help me?

Thank you!
 
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Welcome to PF!

Kiezel said:
the formula Cv = Cp - R is what I have derived from simple formula's like dU = dQ + dW.
If Cp = 4R then Cv = 3R, but why should this be the case?
Careful! ##C_v=C_p-nR## is only true for an ideal gas.

Kiezel said:
according to the equipartition theorem the energy of the degree of freedom is kT/2 thus with 6 degrees of freedom: E=Na6(kt/2)=3RT (because R=Nak)
so now I have an energy which is equal to 3RT

Good. So you have an expression for the thermal energy in terms of ##T##. Remember what heat capacity is: it is a measure of the rate at which the energy of something changes when you change its temperature. Do you think you could apply this definition to your expression for energy to get the heat capacity?
 
Thanks for your reply!

I have defined the heat capacity as:

Heat capacity C is defined as the amount of heat that is necessary to raise T of a standard amount of matter with one degree Kelvin (J/K).

So if my “standard amount of matter” is a mole (because I have used Na in my energy calculation) I can calculate the molar heat capacity. I need to find the difference in energy between T = x and T = x + 1. So if I pick T = 1 then E = 3R and if I pick T = 2 then E = 6R. The difference in energy is 6R – 3R = 3R which would be my molar heat capacity. and thus Cv = 3R

And the Cv = Cp - R part should be omitted because it is not applicable for crystalline solids.

then:
pV = nRT
R = (pV)/(nT) with R in m3 Pa mol-1 k-1 = J mol-1 k-1
this equals Boltzmann constant kb (J K-1) times Avogadro constant Na (mol-1)
and thus R = Nakb (I'm not sure if I have derived it here or not)
and 3R=3Nakb

hopefully this is right
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