Deriving the fourier transform

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SUMMARY

The discussion focuses on deriving the Fourier sine and cosine transforms of the function $$f(x) = e^{-cx}$$ using the exponential form $$e^{iax} = \cos(ax) + i\sin(ax)$$. The integral $$\int_0^{\infty} e^{-cx} e^{iax} dx$$ simplifies to $$\frac{1}{c - ia}$$ after evaluating the limit. The final result can be split into real and imaginary parts, allowing for a direct relationship to the sine and cosine transforms.

PREREQUISITES
  • Understanding of Fourier transforms
  • Familiarity with complex exponentials
  • Knowledge of improper integrals
  • Basic calculus skills
NEXT STEPS
  • Study the properties of Fourier transforms
  • Learn about the applications of Fourier sine and cosine transforms
  • Explore the concept of complex analysis in integrals
  • Investigate the relationship between Fourier transforms and signal processing
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Students in mathematics or engineering, particularly those studying signal processing or applied mathematics, will benefit from this discussion on Fourier transforms.

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Homework Statement



derive the Fourier sine and cosine transforms of $$f(x) = e^{-cx}$$ by using $$e^{iax}=cos(ax)+isin(ax)$$ and computing the integral $$\int_0 ^{\infty} e^{-cx}e^{iax}dx$$.

Homework Equations

The Attempt at a Solution



i'm completely clueless, all i did was evaluate what they told me to.

$$\int_0 ^{\infty} e^{-cx}e^{iax}dx = \int_0 ^{\infty} e^{(ia-c)x}dx$$
$$= \frac{e^{(ia-c)x}}{ia-c}\Big|_0^{\infty} = \frac{cos(ax)+isin(ax)}{ia-c}\Big|_0^{\infty} =-\frac{1}{ia-c}$$
 
Last edited:
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If you split your last result in imaginary and real part, you can relate it to the integrals in your other thread.
 

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