Deriving the Function f(x) = 1/(1+e^x) using Quotient Rule

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Homework Help Overview

The discussion revolves around finding the derivative of the function f(x) = 1/(1+e^x) using the quotient rule in calculus.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the quotient rule and the correctness of the derivative expression. There are attempts to clarify the denominator and the overall sign in the derivative. Some participants express uncertainty about their understanding of the derivative process.

Discussion Status

The discussion is ongoing, with participants providing feedback on each other's attempts. Some guidance has been offered regarding the correct application of the quotient rule, and there is a recognition of errors in the initial attempts. Multiple interpretations of the derivative are being explored.

Contextual Notes

One participant mentions their limited experience with calculus, indicating a potential constraint in their understanding of the topic.

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Homework Statement



Find derivative of function: [tex]f\left(x\right)=\frac{1}{1+e^{x}}[/tex]

Homework Equations



quotient rule.

The Attempt at a Solution



hopefully this is the solution:
[tex]f^{'}\left(x\right)=\frac{e^{x}}{(1+e^{x})^{2}}[/tex]
 
Last edited:
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Really close, but not exactly. Are you sure about the denominator? How is it different from that of the original function?
 
oh, thanks! i had that messed up on my paper too.
 
The derivative is okay up to the overall "-" sign which should be absent in the numerator.
 
i think its fixed now...
 
Still incorrect. Remember that

[tex]\frac{d}{dx}\left(\frac{1}{f(x)}\right)=-\frac{f'(x)}{f^{2}(x)}[/tex]
 
oh, i know this should be easy but I've been studying calculus for only 48 hours, so i appreciate the patience and help.

I could easily rewrite the equation like this [tex](1+e^{x})^{-1}[/tex] and derivate it, but i should know how to do it the other way.
 
Last edited:

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