Deriving the Lorentz transformation

Click For Summary
SUMMARY

The discussion focuses on deriving the Lorentz transformation by assuming linearity and the invariance of perpendicular coordinates. The transformation is expressed as x' = A1 (x - vt), y' = y, z' = z, t' = A2 t + A3 x. The participants emphasize the necessity of ensuring that light travels at speed c in both inertial frames, leading to the equation x'^2 + y'^2 + z'^2 = c^2 * t'^2. The transformation can be represented using matrix multiplication, which simplifies the derivation of constants A1, A2, and A3.

PREREQUISITES
  • Understanding of linear transformations in vector spaces
  • Familiarity with the concept of inertial frames in physics
  • Knowledge of the speed of light as a constant (c)
  • Basic proficiency in matrix multiplication and representation
NEXT STEPS
  • Study the properties of linear transformations in vector spaces
  • Learn how to apply matrix multiplication to coordinate transformations
  • Explore the implications of the speed of light in special relativity
  • Investigate the Galilean transformation and its limitations compared to Lorentz transformation
USEFUL FOR

Students of physics, particularly those studying special relativity, mathematicians interested in linear algebra, and educators seeking to clarify the derivation of the Lorentz transformation.

silmaril89
Messages
85
Reaction score
0

Homework Statement



Derive the Lorentz transformation by assuming that the transformation is linear, and does not change the perpendicular coordinates. Write the transformation as

x' = A1 (x - vt), y' = y, z' = z, t' = A2 t + A3 x,

Determine A1, A2, A3 by requiring that a flash of light produces an outgoing spherical wave, with velocity c, in either frame F or F'

Homework Equations



I believe we can use x'^2 + y'^2 + z'^2 = c^2 * t'^2 to prove it, but I'd like to see if we don't need that

Maybe the Galilean Transformation may also be of use

x' = x - vt, y' = y, z' = z, t' = t

The Attempt at a Solution



All attempts I've made have just been manipulating the two supplied equations above. My biggest problem, is that I can't seem to understand exactly what a linear transformation really is, or what any transformation really is, (at least as far as deriving it myself, or putting it into a matrix). I think once I can understand that, the rest should be trivial. Any help and clarifications on what a linear transformation is and how to apply it to deriving the Lorentz transformation would be greatly appreciated.
 
Last edited:
Physics news on Phys.org
A linear transformation L is a mapping between two vector spaces that has the property

L(rx+sy) = rL(x)+sL(y)

where r and s are scalars and x and y are vectors.

In this problem, the Lorentz transformation maps the coordinates of an event in one inertial frame F to the coordinates of the event in another inertial frame F'. In other words, knowing the coordinates (t, x, y, z) in F, you can calculate the coordinates (t', x', y', z') in F' of the same event.

Requiring the transformation to be linear means that it can be represented by a matrix multiplication:

[tex]\begin{pmatrix}t' \\ x' \\ y' \\ z' \end{pmatrix} = \begin{pmatrix}<br /> \Lambda_{00} & \Lambda_{01} & \Lambda_{02} & \Lambda_{03} \\<br /> \Lambda_{10} & \Lambda_{11} & \Lambda_{12} & \Lambda_{13} \\<br /> \Lambda_{20} & \Lambda_{21} & \Lambda_{22} & \Lambda_{23} \\<br /> \Lambda_{30} & \Lambda_{31} & \Lambda_{32} & \Lambda_{33}<br /> \end{pmatrix} \begin{pmatrix}t \\ x \\ y \\ z \end{pmatrix}[/tex]

Hopefully, you can see that the equations you have can be written in the form above with the appropriate choices for Λμν, so the equations you were given already embody the assumption that the Lorentz transformation is linear.
 
So, as my answer, I wrote my transformation as this

[tex] \begin{pmatrix}t' \\ x' \\ y' \\ z' \end{pmatrix} = \begin{pmatrix}<br /> A2 & A3 & 0 & 0 \\<br /> -A1 v & A1 x & 0 & 0 \\<br /> 0 & 0 & 1 & 0 \\<br /> 0 & 0 & 0 & 1<br /> \end{pmatrix} \begin{pmatrix}t \\ x \\ y \\ z \end{pmatrix}[/tex]

And then from there, I should be able to solve for A1 A2 and A3, by using x'^2 + y'^2 + z'^2 = c^2 * t'^2, is that correct?
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 35 ·
2
Replies
35
Views
5K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
2
Views
1K
Replies
3
Views
2K