Details of the electron cloud in a magnetron: density and size?

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SUMMARY

The discussion focuses on the electron cloud dynamics within a kitchen microwave magnetron, specifically a 10-cavity magnetron operating at 2.45 GHz with an 800W power output. Key parameters include a voltage of approximately 3 kV, a current of 250 mA, and the physical dimensions of the resonant cavities, which are 40 mm in diameter and 15 mm in axial length. The relationship between current and electron density is explored, emphasizing the importance of understanding the electron lifespan in the cavity to calculate the electron charge accurately. The high quality factor (Q) of the cavity, which can reach several thousand, is also discussed in relation to energy storage and loss.

PREREQUISITES
  • Understanding of microwave technology and magnetron operation
  • Familiarity with electrical current and electron charge concepts
  • Knowledge of quality factor (Q) in resonant systems
  • Basic principles of electromagnetic theory
NEXT STEPS
  • Research methods for calculating electron density in magnetrons
  • Learn about the impact of cavity dimensions on microwave frequency generation
  • Explore techniques for measuring Q factor in resonant cavities
  • Investigate the relationship between current, voltage, and electron lifespan in magnetrons
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Engineers, physicists, and technicians involved in microwave technology, magnetron design, and those interested in optimizing microwave performance in kitchen appliances.

cmb
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In a standard kitchen-microwave magnetron, like all magnetrons, a cloud of electrons forms which whizzes around and generates GHz electric currents in an outer ring electrode.

For such a standard kitchen appliance, 800W made with ferrite magnets, what is the typical volume and density of the electron 'charge wheel' that spins around?
 
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There is a picture at the top of this page; https://en.wikipedia.org/wiki/Cavity_magnetron
The size of the resonant cavities in a magnetron is a function of wavelength. For a 10 cavity magnetron producing 2.45 GHz the outside diameter is about 40 mm. The open central cavity surrounding the heated cathode is about 10 mm diameter. The axial length of the cavities is about 15 mm. The two rings are the “Pi strapping” that lock the phase of the cavities and increase efficiency.
Knowing the voltage is about 3 kV and the power 800 watt, the current is about 250 mA.
 
I think the problem here is that "250mA" would not be related to the number of electrons, which have to circulate around the cathode X(?) times to generate that microwave current.

250mA may represent 250mC of electrons entering the working space per second, thus in equilibrium the same number leaving (i.e. a current), but how long do they last in there? If they last for one second then yes there would be 250mC of electrons in the working space. If they last a millisecond then there would be 0.25mC instead.

Is that right? And if so, then how to calculate, and/or measure, that?
 
cmb said:
I think the problem here is that "250mA" would not be related to the number of electrons, which have to circulate around the cathode X(?) times to generate that microwave current.

250mA may represent 250mC of electrons entering the working space per second, thus in equilibrium the same number leaving (i.e. a current), but how long do they last in there? If they last for one second then yes there would be 250mC of electrons in the working space. If they last a millisecond then there would be 0.25mC instead.

Is that right? And if so, then how to calculate, and/or measure, that?
The cavity has a very high Q of several thousand, but it is shunted by the load, which brings the loaded Q down to a low value such as 10. The cavity then stores a lot of energy, such that the energy it loses per cycle is less than the energy stored. Q = 2 pi energy stored/energy lost per cycle. The circulating electrons seem to be equivalent to the circulating current in the cavity and the electrons leaving the system seem equivalent to the load current. So I imagine that the ratio of these two is equal to sqrt Q.
 
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When it is difficult to measure or calculate a parameter we should ask, “why do we need to know the value?”. Once that question is answered we will know how to estimate the parameter.
 
tech99 said:
The cavity has a very high Q of several thousand, but it is shunted by the load, which brings the loaded Q down to a low value such as 10. The cavity then stores a lot of energy, such that the energy it loses per cycle is less than the energy stored. Q = 2 pi energy stored/energy lost per cycle. The circulating electrons seem to be equivalent to the circulating current in the cavity and the electrons leaving the system seem equivalent to the load current. So I imagine that the ratio of these two is equal to sqrt Q.
Very useful, it has prompted me to find some relevant and useful further links.

I had not thought about the magnetron as a device for which the 'Q' is the number of merit, but that has opened that up for me. If you have any further links or direct information on calculating magnetron Q values (if you could PM me and pdfs and such) that'd be really really super helpful.
 

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