Determinant problem in an article about QCD phase diagram

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Ken Gallock
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Hi.
I'm reading an article about QCD phase diagram. https://arxiv.org/abs/1005.4814.
I want to derive eq(20), but I don't know how.
Does anyone know how to derive this?
 
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It just uses that the determinant of a matrix is given by the product of its eigenvalues. The eigenvalues of ##D(0)## come in pairs, ##\gamma_i## and ##\gamma_i^*##. The Mass matrix is proportional to the unit matrix and thus the eigenvalues are ##\gamma_i+m_q## and ##\gamma_i^*+m_q##. Do you get
$$\det (D(0)+m_q)=\prod_i (\gamma_i+m_q)(\gamma_i^*+m_q)$$
which is Eq. (20) in the paper.
 
vanhees71 said:
It just uses that the determinant of a matrix is given by the product of its eigenvalues. The eigenvalues of ##D(0)## come in pairs, ##\gamma_i## and ##\gamma_i^*##. The Mass matrix is proportional to the unit matrix and thus the eigenvalues are ##\gamma_i+m_q## and ##\gamma_i^*+m_q##. Do you get
$$\det (D(0)+m_q)=\prod_i (\gamma_i+m_q)(\gamma_i^*+m_q)$$
which is Eq. (20) in the paper.

Thanks.
If there is no mass, (##m_q=0##), then will it be like this?:
$$
\det D(0)=\prod_i \gamma_i \gamma_i^*.
$$
I'm not familiar with 'a pair (##\gamma_i, \gamma_i^*##)' part. Why do we have to think about pair of eigenvalues?
 
The point is to show that without baryo-chemical potential you have always pairs of conjugate omplex eigenvalues and that's why in this case the fermion determinant is positive. For finite ##\mu_{\text{B}}## it's not longer real (except for imaginary chemical potential). That's why you cannot use Lattice QCD so easily to evaluate the QCD phase diagram at finite ##\mu_{\text{B}}##. Ways out of this trouble is subject of vigorous ungoing research in the nuclear-physics/finite-temperature-lattice community.
 
vanhees71 said:
The point is to show that without baryo-chemical potential you have always pairs of conjugate omplex eigenvalues and that's why in this case the fermion determinant is positive. For finite ##\mu_{\text{B}}## it's not longer real (except for imaginary chemical potential). That's why you cannot use Lattice QCD so easily to evaluate the QCD phase diagram at finite ##\mu_{\text{B}}##. Ways out of this trouble is subject of vigorous ungoing research in the nuclear-physics/finite-temperature-lattice community.
Thanks!
Problem solved.