Determine H for N2 + O2 -> 2NO with Given Information

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The discussion revolves around calculating the enthalpy change (ΔH) for the reaction N2 + O2 -> 2NO using Hess's Law. Participants analyze the provided reactions and their respective enthalpy changes to derive the ΔH for the target reaction. The calculations lead to a final ΔH value of approximately 178.3 kJ, with an emphasis on ensuring the correct units are applied. Additionally, a reference to a related thread on Hess's Law is shared for further clarification. Overall, the participants confirm the accuracy of their calculations for both reactions discussed.
Soaring Crane
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Given the following information:
Fe2O3 + 3CO -> 2Fe + 3CO2 Heat = -28.0 kJ
3Fe + 4CO2 -> 4 CO + Fe3O4 Heat =-12.5 kJ
FInd the heat for the following reaction:
Fe2O3 + CO -> CO2 + Fe3O4
Balance the equation first and remember to include the correct units.

3Fe2O3 + CO -> CO2 + 2Fe3O4

Fe2O3 + 3CO --> 2Fe + 3CO2 H = -28 kJ
2(3Fe + 4CO2 --> 4CO + Fe3O4 H = -12.5 kJ)

3(Fe2O3 + 3CO --> 2Fe + 3CO2 H = -28.0 kJ)
6Fe + 8CO2 --> + 2 Fe3O4 H = -25.0 kJ

3Fe2O3 + 9CO --> 6Fe + 9CO2 H = -84.0
6Fe + 8CO2 --> 8CO + 2Fe3O4 H = -25.0 kJ

Thus, 3Fe2O3 + CO -> CO2 + 2Fe3O4 and H = -109 kJ??


Use the presented information to find the  H for: N2 + O2 ->2NO
1/2 N2 + O2 -> NO2 H = 32.16
4NO + 2O2 ->4NO2 H = -227.9

1/2 N2 + O2 -> NO2 H = 32.16
1/2 (4NO + 2O2 ->4NO2 H = -227.9)

2(1/2 N2 + O2 -> NO2 H = 32.16)
2NO2 --> 2NO + O2 H = +113.95

N2 + 2O2 --> 2NO2 H = 64.32
2NO2 --> 2NO + O2 H = +113.95

Thus, N2 + O2 ->2NO and H = 178.27 = 178.3 ?? I suppose the units are kJ even if they didn't state which units are used?

Thanks.
 
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Any volunteers?

Thanks again.
 
Soaring Crane said:
Any volunteers?

Thanks again.
I get the same numbers on both problems. You're doing good.
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...

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