- #1

snowicorn

- 1

- 0

## Homework Statement

A 3.25 mol sample of an ideal diatomic gas expands adiabatically from a volume of 0.1050 m^3 to 0.762 m^3. Initially the pressure was 1.00 atm

Determine the initial and final temperatures

## Homework Equations

PV

^{γ}= nRT

## The Attempt at a Solution

To get the initial temperature, I used the above equation

*note: converted atm to N/m^2

T = PV

^{γ}/nR = (1.013 *10^5 N/m^2)((0.1050 m^3)^1.4)/ (3.25 mol * 8.314 J/mol*K)

T = 159.8 K

Unfortunately that isn't the correct answer and the correct answer is actually 394 K. I'm pretty sure I'm going through the steps correctly. But no matter how I put the above into the calculator, I keep getting the wrong answer.

All help is appreciated! :)