# Determine the frictional force acting on the box

## Homework Statement

determine the magnitude of the frictional force acting on the box on the plane

f=ma

## The Attempt at a Solution

no clue. help ??

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*imagines there is a support for the slanted green line*

Free Body Diagram, let's go. And we should do this question before you tackle on that tension problem

the tension was part a. this is part b. the force diagram would be the same as the other but without the force of the rope.

Since we are determining friction the equation for the force of friction is required, and in this case so is the angle...

Since we are determining friction the equation for the force of friction is required, and in this case so is the angle...
well there isnt an angle?

I am confused then, can you please give us all known variable? If it is the same as the other thread is the angle not also the same at 60degrees?

the whole problem reads this. two 10 kilogram boxes are connected by a massless string that passes ocer a massless frictionless pulley as shown above( this would be the picture on the other problem) The boxes remaine at rest, with one on the right hanging vertically and the one on the left 2.0meters from the bottom of an inclined plane that makes an angle of 60 degrees with the horizontal. The coefficients of kinetic friction and static friction between the left hand box and the plane are .15 and .30 respectively. You may use g=10m/s^2, sin60=.87, and cos60=.50
a. what is the tension T in string
b. On the diagram below draw and label all forces acting on the box that is on the plane.
c. determine the magnitude of the frictional force acting on the box on the plane.

So the angle is indeed 60, I would start by determining the forces on the box in each direction(i.e. parallel to the plane, normal to the plane)