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## Homework Statement

A 25.0 N weight is held in the outstretched hand of a person with a shoulder-to-elbow length of 26.0 cm and an elbow-to-wrist length of 22.5 cm. The center of the weight is 7.5 cm from the person's wrist.

*A)*Determine the magnitude of the torque about the elbow produced by the weight and

*B)*Determine the magnitude of the torque about the shoulder produced by the weight.

http://educog.com/res/fsu/capalibrary/24equilibrium/Graphics/prob22a.gif

[/URL]## Homework Equations

Well, I can think of a few ways to solve for torque:

t = lF

t

_{net}= I[tex]\alpha[/tex]

t

_{net}= I[tex]\alpha[/tex]

(I = mr

^{2})

(F = ma)

## The Attempt at a Solution

Alright, well, for the first equation I knew that t = lF, where l is the lever arm distance and F is the force in newtons.

l = 30.1

*(a)*, 56.1

*(b)*

F = ma

F = 2.55 x 9.81 = 25 (given)

t = 25 x 30.1 [56.1]

t = 752.5 NM [1403 NM]

**Something is clearly not right here, help! I can tell I'm missing something basic, but I don't know what.**

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