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Determine the nth order Maclaurin polynomial

  1. Nov 30, 2009 #1
    1. The problem statement, all variables and given/known data
    Determine the nth order Maclaurin polynomial for 1/(1-x)2


    2. Relevant equations

    The known Maclaurin polynomial series: 1/(1-x)= 1+x+x2+x3+....+xn +O(xn+1)

    3. The attempt at a solution

    I tried expanding the bottom to get 1/ (1-2x+x2)) then wrote it in the form to match and got 1/(1-(2x-x2) I then proceded to expand..and got 1+ (2x-x2) + (2x-x2)2...+xn +O(xn+1) can anyone tell me if I got it right? Or am I suppose to be doing something else?
     
  2. jcsd
  3. Nov 30, 2009 #2
    Seems reasonable. All you need to do is to write it out as a Maclaurin series, that is to group the same powers of x together in a form [tex]a_n x^n[/tex]

    Alternatively, using the general Taylor series expansion formula you will have easier time finding the constants an.
     
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