Determine the point on the given curve

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Homework Help Overview

The discussion revolves around determining a specific point on a given curve, with participants exploring the format of the answer and the interpretation of coordinates in relation to the problem statement.

Discussion Character

  • Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants are questioning how to express their answers as points with two coordinates, discussing whether to present their findings in the form of (x, y). There is also a mention of rewriting equations to clarify the slope and intercepts.

Discussion Status

The conversation includes attempts to clarify the format of the answer and some participants are providing insights on rewriting equations. However, there appears to be some confusion regarding the equivalence of different forms of equations.

Contextual Notes

There is a mention of a potential mistake in the interpretation of an equation, which may affect the understanding of the problem setup. The discussion also reflects on the need for clarity in expressing answers as points.

ttpp1124
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Homework Statement
I have my answer in an equation, but since it asks for a point, should I simply leave it as b=1.386?
Relevant Equations
n/a
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ttpp1124 said:
Homework Statement:: I have my answer in an equation, but since it asks for a point, should I simply leave it as b=1.386?
Relevant Equations:: n/a

View attachment 262591View attachment 262592
A point (in the context of this problem) has two coordinates, so the answer should be in the form of (x, y).
 
Mark44 said:
A point (in the context of this problem) has two coordinates, so the answer should be in the form of (x, y).
So I'd leave my final answer as (0.693,2.772)?
 
ttpp1124 said:
Homework Statement:: I have my answer in an equation, but since it asks for a point, should I simply leave it as b=1.386?
Relevant Equations:: n/a

View attachment 262591View attachment 262592
You have a mistake right off the bat. 2x + y = 5 is not equivalent to y = 2x + 5.
 
Instead of solving for the intercepts of the line and doing the slope formula, just rewrite the equation of the line in the form ##y=mx+b## then the coefficient ##m## of ##x## is the slope.
 

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