Determine x and y coordinates of resultant force through object

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The discussion focuses on determining the x- and y-coordinates of the resultant force acting on a concrete slab subjected to multiple vertical loads. The resultant force was calculated to be -212 kN, indicating a net downward force. The moments about the x-axis and y-axis were computed, yielding values of -1027 kNm and 552.4 kNm, respectively. Using these moments, the coordinates were derived, resulting in y = 4.8448 and x = -2.60566. The calculations were confirmed to be correct, providing the necessary coordinates for the resultant force's point of action.
Northbysouth
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Homework Statement


The concrete slab supports the six vertical loads shown. Determine the x- and y-coordinates of the point on the slab through with the resultant of the loading system passes.

Image attached


Homework Equations





The Attempt at a Solution



I started off by finding the resultant force. Seeing as how all the forces in the system act in only the z direction I summed them to get:

Rz = 69Kn - 69kN -42kN - 44kN - 67kN - 59kN
= -212 kN

But I'm not sure how I should proceed from this step. I would appreciate any suggestions.
 

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Hi Northbysouth! :smile:

Assume that it goes through the position (x,y).

You know it's -212 kN, so what is the moment of that about the x-axis or the y-axis? :wink:
 
I've managed to solve it now. I did the following:

Rz = -212 kN

Mx = (69kN)(2.3) -(67kN)(3.1+2.3) -(44)(8) -59*(2.3+3.1+2.6)
= -1027. kNm

My = 67*2.3 + 44*6.7 + 69*6.7 -69*5.2
= 552.4 kNm

Mz = 0

M = 1166.224 kNm

Rz*y = -1027.1
y = 4.8448

Rzx = 552.4
x = -2.60566

Thanks for your help.
 

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