Determining Cv Value for Ideal Gases

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Homework Help Overview

The discussion revolves around determining the constant volume heat capacity (Cv) for ideal gases, specifically focusing on air as a diatomic gas. Participants are exploring the relationships between Cv, the constant pressure heat capacity (Cp), and the gas constant (R).

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to derive Cv using the relationship Cp - Cv = R and questions the provided solution of Cv = 1010. Other participants discuss the values of Cv and Cp for air, with some suggesting the use of degrees of freedom to determine Cv.

Discussion Status

Participants are actively engaging with the problem, questioning assumptions about the relationships between Cv and Cp. Some guidance has been offered regarding the definitions of Cv and Cp, but there is no explicit consensus on the approach to take.

Contextual Notes

There is confusion regarding the values of Cv and Cp, particularly in relation to the provided solution. Participants are also grappling with the implications of using different values for R and the degrees of freedom for diatomic gases.

Jaydude
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Stuck on part of this question regarding Cv value:
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I don't understand how one can get the value for Cv,

I tried saying Cp - Cv = R (1)
Cp/Cv = 1.5.so rearrange gives Cp=1.5Cv (2)

Now sub 2 into 1 and that gives 0.5Cv = R
But according to solutions that's wrong, Cv is 1010 and I can't get that value!

Please point me in the right direction,

Kind regards ,

Jay
 
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For air (which is diatomic), Cv = 2.5 R.

Chet
 
Chestermiller said:
For air (which is diatomic), Cv = 2.5 R.

Chet

I see, if R has value 287, then Cv is 717.5 - still not the value used according the solutions which is 1010

Jay
 
Jaydude said:
I see, if R has value 287, then Cv is 717.5 - still not the value used according the solutions which is 1010

Jay
The 1010 value is the constant pressure heat capacity, not the constant volume heat capacity. Divide it by 1.4 to get the constant volume heat capacity.

Chet
 
Chestermiller said:
The 1010 value is the constant pressure heat capacity, not the constant volume heat capacity. Divide it by 1.4 to get the constant volume heat capacity.

Chet

My mistake and confusion - sorry!

I want to start again to make it clear for myself:

In the solutions he uses Cp - R rather than Cv, why? We could have just used value for Cv like you said equal to 2.5R

Ignoring above and continuing like the solutions, how is Cp value obtained? Eg you said it for Cv, what about Cp ? I guess we could times Cv by 1.5 but that defeats the purpose of using Cp - R when we already knew the value of Cv!

(When I try your way of using Cv, the final answer varies slightly)

Kind regards,
 
Last edited:
Jaydude said:
My mistake and confusion - sorry!

I want to start again to make it clear for myself:

In the solutions he uses Cp - R rather than Cv, why? We could have just used value for Cv like you said equal to 2.5R
I don't know why. To figure that out, I would have to be able to read his mind.
Ignoring above and continuing like the solutions, how is Cp value obtained? Eg you said it for Cv, what about Cp ? I guess we could times Cv by 1.4 but that defeats the purpose of using Cp - R when we already knew the value of Cv!
For an ideal gas, Cp = Cv + R. Cv is determined by the number of degrees of freedom of the molecule: Cv=0.5fR. For air at typical temperatures, f = 5, including 3 translational degrees of freedom and 2 rotational degrees of freedom. Even if these relationships are not used, one can always measure the heat capacity of a material.

Chet
 
Chestermiller said:
I don't know why. To figure that out, I would have to be able to read his mind.

For an ideal gas, Cp = Cv + R. Cv is determined by the number of degrees of freedom of the molecule: Cv=0.5fR. For air at typical temperatures, f = 5, including 3 translational degrees of freedom and 2 rotational degrees of freedom. Even if these relationships are not used, one can always measure the heat capacity of a material.

Chet

After researching that I can see what you did there.
For diatomic molecules which is air use Cv = 2.5R . To determine Cp simply use Cp/Cv = k, and usually k is taken as 1.4 unless given.

I used this technique on other questions and it works every time so far, including the question posted above - brilliant!

Thank you!
 

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