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## Homework Statement

Two kilograms of air at 5 bar, 350 K, and 5 kg of carbon monoxide, initially at 4 bar, 450 K, are confined to opposite sides of a rigid, well-insulated container by a partition. The partition is free to move and allows conduction from one gas to the other without energy storage in the partition itself. The air and carbon monoxide each behave as ideal gases with constant specific heat ratio, k = 1.395. Determine the equilibrium temperature.

## Homework Equations

Q - W = delta U

Cp - Cv = R

Cp/Cv = k

R

_{air}= 8.314 / Mwt

_{air}

R

_{co}= 8.314 / Mwt

_{co}

Q = mCv(T2-T1)

## The Attempt at a Solution

Carbon Monoxide

Cp - Cv = 0.297

Cp / Cv = k

Cv(k) - Cv = 0.297

1.395Cv - Cv = 0.297

0.395Cv = 0.297

Cv = 0.75

Air

**Cp - Cv = 0.287**

Cp / Cv = k

1.395Cv - Cv = 0.287

Cv = 0.73

This is where i feel i am going wrong.

Q = mCv(T2-T1)

Q = 0 as insulated closed system

Cp / Cv = k

1.395Cv - Cv = 0.287

Cv = 0.73

This is where i feel i am going wrong.

Q = mCv(T2-T1)

Q = 0 as insulated closed system

Carbon Monoxide Air

0 = 4 x 0.75 (T2 - 450) 0 = 2 x 0.73 (T2 - 350)

0 = 3T2 - 1350 0 = 1.46T2 - 511

I made the two equations equal each other (not sure if that is correct)

1.46T2 - 511 = 3T2 - 1350

839 = 1.54T2

T2 = 544.8 K

I know this is the wrong answer but I am not sure why.

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