Determining Δhloss for Turbulent Flow: Is it the Same?

[williamcarter]

Homework Statement

We know for Laminar flow in which Re<2000 that

$Δhloss=K*\frac{u^{2}} {2g}$

What about if Re>10000 and is turbulent?

Homework Equations

$Δhloss=K*\frac{u^{2}} {2g}$
where $K=\frac{f*4L} {D}$

The Attempt at a Solution

How would Δhloss look like for turbulent flow?Will it be the same?[/B]

 

[Chestermiller]

For laminar flow, f = 16/Re. For turbulent flow, the dependence on Re is more complicated than this and the friction factor also depends on the roughness. This is all captured in the Moody chart, for both laminar and turbulent flow.

 

[williamcarter]

For laminar flow, f = 16/Re. For turbulent flow, the dependence on Re is more complicated than this and the friction factor also depends on the roughness. This is all captured in the Moody chart, for both laminar and turbulent flow.

Thank you for your quick reply.
I understood this, but basically the formula for Δhloss will be the same , in both cases?Also for K formula would be the same in both cases?

Just f changes depending on flow type and roughness right?
I mean f for Laminar is 16/Re and f for Turbulent is intersection between Re and ξ on Moody chart

 

[Chestermiller]

Thank you for your quick reply.
I understood this, but basically the formula for Δhloss will be the same , in both cases?Also for K formula would be the same in both cases?

Just f changes depending on flow type and roughness right?
I mean f for Laminar is 16/Re and f for Turbulent is intersection between Re and ξ on Moody chart

Yes.