How do you find the effective force of Gravity when at a particular latitude?(adsbygoogle = window.adsbygoogle || []).push({});

I keep trying to figure it out, but I can't seem to wrap my head around it. I understand that some small portion of the force of gravity goes towards your centripetal acceleration at certain latitudes, but I can't seem get the idea, since you seem to have three unknowns, but only two equations.

For example (45 degree latitude):

You are not moving in the y-direction, so the y-component of your weight must be equal to the y-component of your normal force; http://ffanxii4ever.googlepages.com/hp1.bmp/hp1-medium;init:.jpg [Broken]

and then the net force in the centripetal acceleration is:

http://ffanxii4ever.googlepages.com/hp2.bmp/hp2-medium;init:.jpg [Broken]

But you only have these two equations, but you have three variables, the normal force, the acceleration of gravity (and as a result the force of gravity) and the angle that the normal force is at (it is offset from the force of gravity).

Does anyone have any idea as to what I am missing, that is making me incapable of understanding this? Thanks.

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# Determining Effective Force of Gravity

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