Determining electric field at origin from semicircle charge

It is ##b d\phi##. Therefore, the charge in an arc of angle ##d\phi## is ##p l b d\phi##. In summary, the provided solution for determining the electric field at the origin due to a semicircular line of charge is correct. The direction of the electric field is -r hat, and the enclosed charge is calculated by multiplying the charge density by the arc length of the half circle.
  • #1
JesseJC
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Homework Statement


A line of charge of uniform density ρl occupies a semicircle of radius b as shown in Fig. P4.10. Use the material presented in Example 4-4 to determine the electric field at the origin.

Homework Equations


dE = kdQ/r^2

The Attempt at a Solution


I'm trying to understand the solution given in the solutions manual, here it is:

http://www.zmuda.ece.ufl.edu/Fields_1_Spring 2013/4-1.10.pdf

1. Why is the direction -r hat, rather than just r hat?
2. Why is the enclosed charge Q stated as (pl)(b)? Shouldn't it be pl multiplied by the arc length of the half circle? I understand that I'm wrong and the solution is right, but I do not understand why the charge density would be multiplied by the radius.
 
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  • #2
1. The electric field felt at the origin due to the charge ##dE## at position ##\hat{\mathbf{r}}## points from ##\hat{\mathbf{r}}## toward the origin. (Recall that a positive ##dE## would exert a repulsive force on a positive test charge at the origin.)

2. What is the arc length at radius ##b## that subtends the angle ##d\phi##?
 

What is the concept of determining electric field at the origin from semicircle charge?

The concept of determining electric field at the origin from semicircle charge involves using the principles of electrostatics to calculate the electric field strength at a specific point, in this case, the origin, due to a semicircular distribution of charge.

What is the formula for calculating electric field at the origin from semicircle charge?

The formula for calculating electric field at the origin from semicircle charge is E = (1/4πε0) * (√2Q / R), where Q is the total charge of the semicircle and R is the radius of the semicircle.

How do you determine the direction of the electric field at the origin from semicircle charge?

The direction of the electric field at the origin from semicircle charge can be determined by using the right-hand rule. Place your right hand with your fingers pointing in the direction of the charge and your thumb pointing towards the origin. The direction your palm is facing represents the direction of the electric field.

What factors affect the electric field at the origin from semicircle charge?

The electric field at the origin from semicircle charge is affected by the magnitude of the charge, the distance from the origin, and the shape of the semicircle. The closer the charge is to the origin and the larger the magnitude of the charge, the stronger the electric field will be.

How is the electric field at the origin from semicircle charge related to the electric potential?

The electric field at the origin from semicircle charge is directly related to the electric potential. The electric potential is the amount of work needed to move a positive charge from infinity to a specific point, and the electric field is the force experienced by a positive charge at that point. The electric potential is the negative gradient of the electric field, meaning that the stronger the electric field, the greater the change in electric potential.

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