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A battery of unknown EMF and internal resistance is connected in series with an ammeter and a resistance box. The current was 2.0A when R= 4.0 Ohms and 1.5A when R= 6.0 Ohms. Calculate the EMF and internal resistance.

I feel you may have to arrange this somehow although I am probably wrong:

Internal resistance = v1-v2/I2-I1

I have had no attempt at a solution as I am utterly confused by this question.

Thank you for reading.

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