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**hi guys im swamp with work and have not been able to go through my assignments proper**

**1. one cube meter of an ideal gas at 600K and 1000Kpa expands to 5 times its initial volume: by mechanically reversible, isothermal process and by a mechanically reversible, adiabatic process**

**2.for each case calculate the final temperature, pressure, and the work done by the gas. take Cp= 21 J/mol.K**

**3. For isothermal process:**

T2= 600

P1V1=P2V2

thus P2= (1*1000)/5 =200Kpa

W= -P1V1 ln V2/V1

= -(1000000000*1) ln (5/1)

= -1609.438 KJT2= 600

P1V1=P2V2

thus P2= (1*1000)/5 =200Kpa

W= -P1V1 ln V2/V1

= -(1000000000*1) ln (5/1)

= -1609.438 KJ