- #1
nombusoz
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hi guys I am swamp with work and have not been able to go through my assignments proper
1. one cube meter of an ideal gas at 600K and 1000Kpa expands to 5 times its initial volume: by mechanically reversible, isothermal process and by a mechanically reversible, adiabatic process
2.for each case calculate the final temperature, pressure, and the work done by the gas. take Cp= 21 J/mol.K
3. For isothermal process:
T2= 600
P1V1=P2V2
thus P2= (1*1000)/5 =200Kpa
W= -P1V1 ln V2/V1
= -(1000000000*1) ln (5/1)
= -1609.438 KJ
1. one cube meter of an ideal gas at 600K and 1000Kpa expands to 5 times its initial volume: by mechanically reversible, isothermal process and by a mechanically reversible, adiabatic process
2.for each case calculate the final temperature, pressure, and the work done by the gas. take Cp= 21 J/mol.K
3. For isothermal process:
T2= 600
P1V1=P2V2
thus P2= (1*1000)/5 =200Kpa
W= -P1V1 ln V2/V1
= -(1000000000*1) ln (5/1)
= -1609.438 KJ