Determining Minimum Height to Complete a Loop

Click For Summary
SUMMARY

The minimum height required for a rider with a mass of 80.0 kg to complete a loop with a radius of 10.0 meters is established as 25 meters, derived from the principle of Conservation of Energy and Newton’s Second Law. At the top of the loop, the potential energy is expressed as mg(2r), leading to the conclusion that h must equal 2.5 times the radius (2.5r). This analysis emphasizes the importance of understanding both energy conservation and the forces acting on the cart during the ride.

PREREQUISITES
  • Understanding of Conservation of Energy principles
  • Familiarity with Newton’s Second Law of Motion
  • Basic knowledge of potential and kinetic energy calculations
  • Concept of circular motion dynamics
NEXT STEPS
  • Study the application of Conservation of Energy in mechanical systems
  • Explore detailed examples of Newton’s Second Law in circular motion
  • Learn about potential and kinetic energy transformations in physics
  • Investigate real-world applications of loop-the-loop dynamics in roller coasters
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in the dynamics of circular motion and energy conservation principles.

crushedcorn
Messages
7
Reaction score
0
This question was posted on Khan Academy. I attempted it after watching all of their great Work and Energy videos, but the way they arrived at the answer was way above my skill level even after reviewing the videos a number of times. Here is the question:

What is the minimum height h of a slope that must be constructed in order for a rider in the cart with a combined mass m = 80.0 kg to complete the loop with a radius r = 10.0 meters safely, assuming a frictionless trip?

4e906cd94e8d150a1b45f273793579c77b38f5e6.png

How would you answer this question? The way that they arrived at their answer is below. Is there any alternative/more concise way to arrive at the same answer? I would have never guessed to proceed in the way noted in Hint #3.

We can use the Conservation of Energy formula to evaluate these two points: at the top of the hill and at the top of the loop.

caffd013cb948bf84803ad975be9a21722638d0a.png

Hint #2
At the top of the hill, the kinetic energy is zero, and the potential energy is mgh.

863284b2d565dbf72b029fb3e30cc3989ddc2627.png

Hint #3
At the top of the loop, we must derive another formula to connect ideas together by using Newton’s Second Law to describe the forces acting on the cart and then to solve for v:

d26b49c5ae2f46c757736dc22d56742fe0011f3c.png

Hint #4
This expression is for the velocity at the top of the loop since there is no normal force only at that point. Additionally, h = 2r such that the potential energy is mg(2r).

40419bee3dd2001dd8df7d462b1a36a7f664028c.png

Hint #5
The correct answer is 2.5. Since the radius of the loop is 10 meters, then 2.5r is 25 meters.
 
Physics news on Phys.org
crushedcorn said:
This question was posted on Khan Academy. I attempted it after watching all of their great Work and Energy videos, but the way they arrived at the answer was way above my skill level even after reviewing the videos a number of times.

I believe this is the easiest and smallest way to answer this question - I would certainly have solved the question this way .

Does this answer your doubt ?

crushedcorn said:
I would have never guessed to proceed in the way noted in Hint #3.

Do you know your circular motion ?
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 19 ·
Replies
19
Views
7K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 12 ·
Replies
12
Views
13K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
4
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
24
Views
7K
Replies
9
Views
4K