Determining perpendicular tangent line

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Homework Help Overview

The discussion revolves around finding points on the graph of the function f(x) = √(2x+1) where the tangent line is perpendicular to a given line represented by the equation 3x + y + 4 = 0. The problem involves concepts from calculus, specifically derivatives and the properties of slopes of lines.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need to find the derivative of the function to determine the slope of the tangent line. There is a focus on understanding the relationship between the slopes of perpendicular lines, with one participant noting that a perpendicular slope to -3 would be 1/3. Questions arise regarding the application of the derivative and the method to find where the tangent line meets this slope.

Discussion Status

The discussion is active, with participants exploring the implications of the derivative and its relation to the tangent line's slope. Some guidance has been offered regarding the relationship between slopes, but there is no explicit consensus on the next steps or methods to be used.

Contextual Notes

Participants are navigating the notation used for the function and expressing preferences for clearer representations. There is also mention of potential confusion regarding the application of rules related to derivatives.

Thendi
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Homework Statement


Determine the coordinates of the points on the graph of f(x) = _/'2x+1 where the tangent line is perpendicular to the line 3x+y+4 = 0

_/' -means square root

Homework Equations


f(x) = _/'2x+1
3x+y+4 = 0

The Attempt at a Solution


I made it equal to y
like y= -3x-4...do I have to find the derivative of f(x) = _/'2x+1
Can somebody show me what I am suppose to do next?
or step by step would be fine too.
 
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What does the derivative of f(x) tell you about, the tangent line?
 
Okay, y= -3x- 4 which means it has slope -3. And that tells you than a perpendicular line must have slope 1/3. Where on the curve does the tangent line have slope 1/3?

By the way, just "sqrt(2x+1)" if a far superior notation to "_/'2x+1".
 
I found the derivative of sqrt(2x+1) which is (2x+1)1/2
Where on the curve does the tangent line have slope 1/3?
Do you use the chair rule?
 

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