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Determining secant/cosecant equations for a graph

  1. Apr 6, 2009 #1
    1. The problem statement, all variables and given/known data

    http://img18.imageshack.us/img18/2097/56413287.jpg [Broken][/URL]


    3. The attempt at a solution

    I believe that the Secant curve has the equation y = 3 Sec ( x - pi/4) However I'm having difficulty figuring out what the cosecant equation would be. Wouldn't it just be the same thing but with a csc instead of sec?
     
    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. Apr 6, 2009 #2

    tiny-tim

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    Hi Random-Hero-! :smile:
    Nooo (except for the 3) …

    what is the period?

    Hint: draw the inverse graph first … that should help you with both parts of the question :wink:
     
  4. May 6, 2009 #3
    would it be these?

    secant: -3sec(4x)

    cosecant: -3csc(4x+pi/2)
     
  5. May 7, 2009 #4

    tiny-tim

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    I think you're just guessing :rolleyes:

    try again, and this time give your reasons for your answer :smile:

    (remember, sec = 1/cos, and csc = 1/sin)

    (and what is the period?)
     
  6. May 7, 2009 #5
    I'm just totally lost, I genuinely have NO idea what I'm doing, I just punched those into my Ti-83 and the graph that came up looked identical, but I want to figure it out by eye. Is there a site that covers this somewhere with reciprocal trig?
     
  7. May 7, 2009 #6

    tiny-tim

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    ok, try this …

    draw the inverse of the graph …

    you have a graph of y against x

    in pencil, draw 3/y against x (it'll be in the middle, and it should be a continuous wave) …

    can you write that pencil graph as a cos or sin? :smile:
     
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