# Homework Help: Determining secant/cosecant equations for a graph

1. Apr 6, 2009

### Random-Hero-

1. The problem statement, all variables and given/known data

http://img18.imageshack.us/img18/2097/56413287.jpg [Broken][/URL]

3. The attempt at a solution

I believe that the Secant curve has the equation y = 3 Sec ( x - pi/4) However I'm having difficulty figuring out what the cosecant equation would be. Wouldn't it just be the same thing but with a csc instead of sec?

Last edited by a moderator: May 4, 2017
2. Apr 6, 2009

### tiny-tim

Hi Random-Hero-!
Nooo (except for the 3) …

what is the period?

Hint: draw the inverse graph first … that should help you with both parts of the question

3. May 6, 2009

### Random-Hero-

would it be these?

secant: -3sec(4x)

cosecant: -3csc(4x+pi/2)

4. May 7, 2009

### tiny-tim

I think you're just guessing

(remember, sec = 1/cos, and csc = 1/sin)

(and what is the period?)

5. May 7, 2009

### Random-Hero-

I'm just totally lost, I genuinely have NO idea what I'm doing, I just punched those into my Ti-83 and the graph that came up looked identical, but I want to figure it out by eye. Is there a site that covers this somewhere with reciprocal trig?

6. May 7, 2009

### tiny-tim

ok, try this …

draw the inverse of the graph …

you have a graph of y against x

in pencil, draw 3/y against x (it'll be in the middle, and it should be a continuous wave) …

can you write that pencil graph as a cos or sin?