- #1
Karol
- 1,380
- 22
Homework Statement
The two graphs are possible legitimate representations of ##y=\sec^{-1}(x)##.
The derivative is positive on all the domain and so is graph A, but graph B has negative tangent when x<-1
Homework Equations
Derivative of inverse secant:
$$(\sec^{-1}(x))'=\frac{1}{x(\pm\sqrt{x^2-1})}$$
The Attempt at a Solution
The derivative was established on all the domain, so i think it must be positive. the slope must be pointing upwards on all the domain.
I don't know.