Determining the Frequency Heard by a Helicopter from a Parachutist's Shout

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Homework Help Overview

The problem involves a parachutist who shouts while in free fall from a hovering helicopter, and the task is to determine the frequency of the shout as heard by the helicopter. The subject area pertains to wave phenomena and the Doppler effect in the context of sound.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of the parachutist's speed after 4 seconds of free fall and its implications for the Doppler effect. There are questions about the correct application of the Doppler effect formula and the signs used in calculations.

Discussion Status

Some participants have provided guidance on calculating the speed of the parachutist and the correct interpretation of the Doppler effect equations. There is an ongoing exploration of the calculations, with some participants expressing confusion over the results and signs used in their computations.

Contextual Notes

Participants note that the parachutist is in free fall and that the parachute has not yet been deployed, which is relevant for determining the speed. There is also mention of the helicopter's noise level potentially affecting the clarity of the sound heard.

nickb145
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Homework Statement



A parachutist leaps from a hovering helicopter, after 4.0s of freefall shouts back at 425Hz. What frequeny is heard at the helicopter?

Homework Equations



f'=f/(1+Vs/V)Vsource=?
f'=?
f=425Hz
V=343m/s

The Attempt at a Solution

I'm stuck on finding the speed for the jumper. I'm sure it's simple but i just can't think of it for somereason.
 
Last edited:
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nickb145 said:

Homework Statement



A parachutist leaps from a hovering helicopter, after 4.0s of freefall shouts back at 425Hz. What frequeny is heard at the helicopter?

Homework Equations



f'=f/(1-Vs/V)


Vsource=?
f'=?
f=425Hz
V=343m/s

The Attempt at a Solution




I'm stuck on finding the speed for the jumper. I'm sure it's simple but i just can't think of it for somereason.


Read the problem carefully. It is free-fall, the parachute is not yet opened . What is the speed of a falling body after 4 s?

ehild
 
thinking
 
Last edited:
ehild said:
Read the problem carefully. It is free-fall, the parachute is not yet opened . What is the speed of a falling body after 4 s?

ehild


vy=Vyi-gt right?

initial speed is 0 so its just -9.8*4=-39.2
 
Yes, it is the velocity if you consider upward positive.
The parachuter shouts back. How is his sound heard on the helicopter? (Hm. The helicopter is very noisy --think it is a super helicopter making only low noise so the parachuter's sound can be heard :wink:)


ehild
 
But it is strange that i get a higher frequency of what it should be. The answer is 381.4 and i keep getting 479. I'm getting my signs wrong somewhere...

I used f'=f/(1+Vs/V) for a source moving away from reciever.
 
You need to calculate with the speed of moving away. The speed is positive, magnitude of velocity. Substitute Vs=39.2 m/s.

ehild
 

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