Determining the time intervals

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The discussion focuses on calculating the time intervals between failures of a relay, modeled by an exponential distribution with a failure rate of 2 x 10^-7 per hour. Users are attempting to determine the time intervals corresponding to 99%, 95%, 50%, 1%, and 0.1% probabilities of being exceeded. One participant reports calculated values of 5.7 years for 99%, 29.3 years for 95%, 394.6 years for 50%, 2628.5 years for 1%, and 3942.8 years for 0.1%. The conversation seeks clarification on these results and the methods used to arrive at them.
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Homework Statement


Assuming that the random time to failure of a relay is exponentially distributed with a failure rate lambda of 2 x 10^-7 per hour, determin ethe time intervals between failures(years) which have 99%, 95%, 50%, 1%, and 0.1% probabilities of being exceeded


Homework Equations



Reliability function 1- the cumulative distribution function


The Attempt at a Solution



putting in the values of lambda 2 X 10^-7 and hours per year of (24 x 31 x 12) my value is way off the mark for 99% which is 5.7, incidentally 95%, 50%, 1%, and 0.1% are 29.3, 394.6, 2628.5, and 3942.8
 
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What is your value, and how did you arrive at it?
 
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