Determining Wave Direction using Doppler Effect

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To determine the direction of a traveling wave represented by the equation cos(ax±bt), one can utilize the Doppler Effect, which indicates that a lower frequency suggests the wave is moving away from the observer, while a higher frequency indicates it is approaching. This method is effective for identifying the wave's propagation direction. Additionally, a more straightforward approach involves analyzing the wave's phase. By setting the phase constant (kx±ωt=constant), one can derive the wave velocity. For the equation with a plus sign, the wave travels in the positive x-direction, while with a minus sign, it travels in the negative x-direction. Both methods are valid for determining wave direction, with the phase analysis being the simpler option.
tinksy
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I have a question regarding waves which has been bugging me for a while:

"You are given a traveling wave with an equation of the form
cos(ax+/-bt)
where x and t are position and time as usual, a and b are positive numbers. Explain how you would physically determine the direction that the wave is traveling in"


Here are my ideas:

I'm assuming that we only need to determine the 'direction' ie positive or negative direction in which the wave is traveling, so it's one dimensional. This means we can use the Doppler Effect. If we choose an arbitrary direction on the line to travel, the direction which gives an apparently lower frequency than expected is going away from the source, and the direction which gives a higher frequency is going towards the source. Since the wave always travels away from the source, we can determine the direction of wave propagation.

Is this right?
 
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The Doppler effect is one way to do it, but don't forget that if we are talking about something other than light waves, we have to transform the velocity of the wave as well.

A more straightforward way of doing it would be to note that, for plane waves, the phase of the wave is a constant[/color]. From this, we can deduce the direction of the wave velocity.

y(x,t)=cos(kx+ωt)
kx+ωt=constant
k(dx/dt)+ω=0
dx/dt=-ω/k

Since dx/dt<0, this wave is traveling in the negative x-direction.

y(x,t)=cos(kx-&omega;t)
kx-&omega;t=constant
k(dx/dt)-&omega;=0
dx/dt=+&omega;/k

Since dx/dt>0, this wave is traveling in the positive x-direction.
 
cheers tom :smile:

so would that be considered a physical way of determining the direction of the wave?
 
Yes, it would--but so would yours.

The difference is, my way would be considered the easy way! :wink:
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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