# Development of Bernoulli's equation

## Main Question or Discussion Point

My book says:

$\frac{\partial V}{\partial s}\frac{ds}{dt}=-\frac{1}{\rho}\frac{dP}{ds}-g\frac{dz}{ds}$ (1.28)

The changes of pressure as a function of time cannot accelerate a fluid particle. This is because the same pressure would be acting at every instant on all sides of the fluid particles. Therefore, the partial differential can be replaced by the total derivative in Eq. (1.28)

$V\frac{dV}{ds}=-\frac{1}{\rho}\frac{dP}{ds}-g\frac{dz}{ds}$

I can't understand the explanation. Please, help me.

## Answers and Replies

Related Classical Physics News on Phys.org
The changes of pressure as a function of time cannot accelerate a fluid particle.
You need pressure to change as a function of space (position) to impart acceleration. That is you must have a a pressure difference at the same time.