- #1

nomadreid

Gold Member

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suppose you have a one-place formula A(.) with domain the set of codes of sentences.

I use quotation marks in this way : "M" is the code of M.

Define the 2-place relation sub:

If x ="f(.)", then sub(x,x) = "f(x)"

Define B(x) as A(sub (x,x))

Define S as B("B(x)")

retracing, S is true iff A("S") is.

Nice. What I do not understand is that the proof notes that S and A("S") are equivalent but not the same. It appears to me from the construction that they are the same. What am I missing?

Thanks.