Diameter 0.8 m height 1.2 m floats in water

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Discussion Overview

The discussion revolves around a physics homework problem involving a cone with a diameter of 0.8 m and height of 1.2 m floating in a liquid with a density of 1360 kg/m³. Participants are exploring how to determine the volume of the submerged portion of the cone and how far it will sink in the liquid.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant expresses uncertainty about finding the volume of the submerged cone and seeks assistance.
  • Another participant suggests writing a variable as a function of the length to aid in the calculations.
  • A different participant proposes a relationship based on the density of the liquid compared to water, indicating that the cone will float but questions whether it will sink slightly, using a ratio derived from the dimensions of the cone.
  • A subsequent reply challenges the previous participant's reasoning and provides a different hint involving a ratio of dimensions.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus, as there are differing views on the behavior of the cone in the liquid and the appropriate method for calculating the submerged volume.

Contextual Notes

There are limitations in the assumptions made regarding the cone's behavior in the liquid, as well as the dependence on the definitions of the variables used in the calculations.

darkmagic
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Homework Statement



Given:
diameter 0.8 m
height 1.2 m
floats in water
how far will it sink in a liquid (density =1360 kg/m^3)

Homework Equations



Buoyant force

The Attempt at a Solution



In the attachment
I'm stuck on how to find the volume of the submerged cone in the liquid
please help
 

Attachments

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You are doing well, so far. Hint 1: Write d (or r, or x) as a function of L.
 


This what I think: since the liquid is more dense than water, then the cone will float a little. From triangle, 0.8 becomes 0.8+y and 0.4 becomes 0.4-y. The ratio and proportion becomes 0.4/1.2 = x/(0.8 + y). Am I correct? or the cone will sink a little?
 
No. Hint 2: 0.4/1.2 = x/L.
 

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