Diameter of Earth-like planet / gravitational force

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SUMMARY

The discussion centers on calculating the necessary increase in Earth's mass and diameter for an average person to weigh an additional 50 pounds. It is established that to achieve this, the radius of Earth must increase by approximately 30%, resulting in a corresponding increase in diameter. The relationship between mass, radius, and gravitational force is governed by the formula G ~ M/R², indicating that surface gravity is proportional to density times radius. Participants also highlighted the importance of density in these calculations, emphasizing that an Earth-like planet must maintain similar density characteristics.

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  • Understanding of gravitational force and its relation to mass and radius
  • Familiarity with the formula G ~ M/R²
  • Basic knowledge of density and its implications in planetary science
  • Ability to perform ratio calculations and understand proportional relationships
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  • Research the implications of changing planetary density on gravitational force
  • Explore the effects of varying mass and radius on surface gravity
  • Learn about the characteristics of Earth-like exoplanets and their potential for habitability
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Astronomers, astrophysicists, planetary scientists, and educators interested in gravitational physics and the characteristics of Earth-like planets.

chris2112
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I kind of have a stupid question. How much more massive would the Earth have to be for the average person to weigh about 50 more pounds? How much bigger could the Earth's diameter be? Thanks.
 
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There isn't a single number. Decreasing the radius of the Earth while keeping the mass the same would increase the weight of a person on the surface. You could also keep the Earth the same radius but increase the mass to get the same effect. Or any combination of the two.
 
chris2112 said:
I kind of have a stupid question. How much more massive would the Earth have to be for the average person to weigh about 50 more pounds? How much bigger could the Earth's diameter be? Thanks.

Let's say average weight for women is 145 pounds and for men 185 pounds and average "person" weighs 165 pounds.

Lets say "earth-like" means roughly same DENSITY because roughly same chemical composition---iron core, rocky mantle, crust etc etc.

So you want the size for which the 165 pound person will weigh 50 more pounds, or 215. So you want gravity to be stronger by a factor of 215/165.

So you want the RADIUS to increase by that same factor.

So calculate what 215/165 is. About 1.3.

So with those assumptions (about "average person" and "earth-like") the answer is that the radius would need to be about 30% bigger.
IOW the diameter would need to be about 30% bigger.
 
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marcus, I am not following your logic. Ifd the radius increased by 30%, the mass would increase by 2.2. Are you accounting for that?
 
DaveC426913 said:
marcus, I am not following your logic. Ifd the radius increased by 30%, the mass would increase by 2.2. Are you accounting for that?
You'd also be 30% farther away from the centre of the gravitational field. Marcus is correct.
 
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G ~ M/R^2
Surface gravityp ~ M/R^3
Density

G ~ p x R
 
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True, TEFL. The surface gravity is proportional to the density times the radius.

BTW at the top of the blank space where we write replies there is this line of symbols B I U ... Σ
and if you click on the the Σ you get a convenient menu of symbols including the lowercase Greek rho (ρ) which is normally used for density.

There's also an x2 symbol you can click on to write superscripts. So your second equation could be written ρ ~ M/R3

You may have discovered this already, but in case not I wanted to mention it. Very handy.

I do write the ^ for superscripts when I want to use the google calculator, to be able to paste the formula into the google window and have it evaluate it. The calculator likes to have exponents written in the x^2 form. But for purely human consumption it looks better to use the PF symbols gadget.
 
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